A: Mikhaylo-Aleksandrovskiy city of country Russian Federation lies on the geographical coordinates of 49° 12' 29" N, 40° 14' 52" E.
Latitude and Longitude of the Mikhaylo-Aleksandrovskiy city of Russian Federation in other units:
| Unit | Latitude | Longitude |
| Latitude and Longitude to decimals | 60.0 | 100.0 |
| Latitude and Longitude to degrees minutes seconds | 49° 12' 29" N | 40° 14' 52" E |
| Latitude/Longitude to UTM Reference |
| UTM Northing:5451338.932935734 Easting:590885.2877986023 Zone:37U |
| View Latitude of Russian Federation. |
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