A: Aleksandro-Sergiyevka city of country Russian Federation lies on the geographical coordinates of 52° 14' 0" N, 51° 32' 0" E.
Latitude and Longitude of the Aleksandro-Sergiyevka city of Russian Federation in other units:
| Unit | Latitude | Longitude |
| Latitude and Longitude to decimals | 60.0 | 100.0 |
| Latitude and Longitude to degrees minutes seconds | 52° 14' 0" N | 51° 32' 0" E |
| Latitude/Longitude to UTM Reference |
| UTM Northing:5787120.92802812 Easting:536420.4739755042 Zone:39U |
| View Latitude of Russian Federation. |
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